0=4x-x^2/3

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Solution for 0=4x-x^2/3 equation: 


x in (-oo:+oo)

0 = 4*x-((x^2)/3) // - 4*x-((x^2)/3)

(x^2)/3-(4*x)+0 = 0

(x^2)/3-4*x = 0

1/3*x^2-4*x = 0

DELTA = (-4)^2-(0*1/3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+4)/(1/3*2) or x = (4-16^(1/2))/(1/3*2)

x = 12 or x = 0

x in { 0, 12 }

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